如何使用 `enumerate` 迭代 `dict` 并解压索引、键和值以及迭代

Question

How to iterate dict with enumerate such that I could unpack the index, key and value at the time of iteration?

Something like:

for i, (k, v) in enumerate(mydict):
    # some stuff

I want to iterate through the keys and values in a dictionary called mydict and count them, so I know when I'm on the last one.

Answer 1

Instead of using mydict , you should be using mydict.items() with enumerate as:

for i, (k, v) in enumerate(mydict.items()):
    # your stuff

Sample example:

mydict = {1: 'a', 2: 'b'}
for i, (k, v) in enumerate(mydict.items()):
    print("index: {}, key: {}, value: {}".format(i, k, v))

# which will print:
# -----------------
# index: 0, key: 1, value: a
# index: 1, key: 2, value: b

Explanation:

• enumerate() returns an iterator object which contains tuples in the format: [(index, list_element), ...]
• dict.items() returns an iterator object (in Python 3.x. It returns list in Python 2.7) in the format: [(key, value), ...]
• On combining together, enumerate(dict.items()) will return an iterator object containing tuples in the format: [(index, (key, value)), ...]