将字符串拆分为键和值对

Question

I am spliting string with '&' . For Example:

password=XXXXXXXXX&username=XXXXXXXXXXX

Now if suppose my password contains '&' then i am facing issue here that the password gets trimed on first occurence of '&'.

Example:

password=disney&123&username=XXXXXXXXXXX

So my output will be as follows:

password=disney 
123 
username=XXXXXXXXXXX

But I want my output as:

password=disney&123 
username=XXXXXXXXXXX

Please guide me as i am new to java. And i want to split the string using '&' only and my password may conatin '&' it depends on users.

Thanks in Advance, Ritesh

Answer 1

A more simple solution would be to use the URL encoding completly. Here you are using only the separator system but you should also use the encoding.

So when you build the String, encode the values, this will replace some character, you can use the complet solution or simply replace the & with the value of your choice (but I would not do that).

Then, when you have split the String contains only the & used to separate values, decode the values (to recreate the original values).

This would be exactly the same as sending a request to a WebService, since you use the same pattern, this would seems more logic.

• Encode the values
• Concat the values with &
• Send the String
• Split the String using &
• Decode the values

Answer 2

String[] strs="password=disney&123&username=XXXXXXXXXXX".split("&username=");
strs[1]="username="+strs[1];
System.out.println(strs[0]);
System.out.println(strs[1]);

--

Edit:

//This is a slightly more generalized method
String[] strs="username=XXXXXXXXXXX&password=disney&123".split("&(?=(username|password)=)");
System.out.println(strs[0]);
System.out.println(strs[1]);

--

Edit:

//more generalized method
String[] strs="username=XXXXXXXXXXX&password=disney&123".split("&(?=([a-zA-Z0-9]+)=)");
for(String str : strs)
    System.out.println(str);