C＃将Xml属性反序列化为值，而不用类包装它

Question

I'm trying to deserialize xml below:

<venue href="http://SomeUrl">
   <location id="ABC"/>
   <title>Some title</title>
</venue>

When I wrap it with class like below XmlSerializer works like charm

[XmlRoot(ElementName = "venue")]
public class VenueModel
{
    [XmlElement("location")]
    public Location Location;

    [XmlElement("title")]
    public string Title;

    [XmlAttribute("href")]
    public string Href;
}

public class Location
{
    [XmlAttribute("id")]
    public string Id;
}

But in my opinion wrapping simple string from Location into separate class it's quite dull solution. What I would like to achieve is to create simpler flatten model like below:

[XmlRoot(ElementName = "venue")]
public class VenueModel2
{
    [SomeMagicAttribute]
    public string LocationId;

    [XmlElement("title")]
    public string Title;

    [XmlAttribute("href")]
    public string Href;
}

so first question? is it possible using C# System.Xml.Serialization ? If it is, what is the magic attribute to get this data?

Answer 1

what I found is that first i need to apply xsl translation (as the one below) to input xml

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="xml" encoding="utf-8" indent="no"/>
       <xsl:template match="/">
          <venue>
             <href><xsl:value-of select="/venue/@href" /></href>
             <locationId><xsl:value-of select="/venue/location/@id" /></locationId>
             <title><xsl:value-of select="/venue/title" /></title>
          </venue>
    </xsl:template>
</xsl:stylesheet>

and then output xml looks like this:

<venue>
   <href>SomeUrl</href>
   <locationId>ABC</locationId>
   <title>Some title</title>
</venue>

which than can be deserialised to the form i want it to be. and applyink this translations in C# code is described here: C# How to perform a live xslt transformation on an in memory object?