自定义array.sort函数，包含多个条件。 布尔

Question

I have an array of objects that i would like to order by several properties.

Im going to showcase a single element of the array

var ele = {
    id: INT, various,
    priority: INT 1 - 10,
    shooterid: INT various,
    targetid: INT various,
    flight: BOOL
}

i would like to order the array according to some criteria and i can do the sort by priority, shooter and target by using

if (a.priority != b-priority){
  return a-priority - b-priority;
else if a.shooterid != b.shooterid){
  return a.shooterid - b. shooterid
}
else return a.targetid - b.targetid

However, i also want to sort by flight and i would like to all elements with flight = true to be sorted LAST in addition to the above sort.

I tried if (a.flight){return -1/0/1} a the very top of the above if/self (adding else to the formerly if) but it didnt work...

How can i extend the sort to include for the BOOL prop ?

Answer 1

You could combine all sort criteria with logical or || , even the boolean values.

 var data = [{ id: 0, flight: true, priority: 1, shooterid: 2, targetid: 1 }, { id: 1, flight: true, priority: 2, shooterid: 2, targetid: 3 }, { id: 2, flight: false, priority: 1, shooterid: 1, targetid: 2 }, { id: 3, flight: false, priority: 2, shooterid: 1, targetid: 1 }, { id: 4, flight: true, priority: 1, shooterid: 1, targetid: 2 }]; data.sort(function (a, b) { return ( a.flight - b.flight || a.priority - b.priority || a.shooterid - b.shooterid || a.targetid - b.targetid ); }); console.log(data); 

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Answer 2

The first if should be:

if (a.flight != b.flight)
  return a.flight - b.flight;

In the subtraction, boolean true will be treated as 1 and false as 0 . That means that the false ones will sort before the true ones, as you say you want.