如何在成功回调函数中获取$ .ajax（）请求参数？

Question

I want get ajax data parameter at success callback function

like bellow

$.ajax({
     url: 'example.com/something',
     method: 'GET',
     data: { 'sample':'test' }, // => I want this data in success function.
     success: function(response, textStatus, jqXHR){
          // want get data parameter
          // {'sample':'test'}

          // someone answered that could get below code but I couldn't get it 
          // console.log(this.data);  => X 
     }
});

Answer 1

Should just be able to type data.sample in the success handler to get the value. Alternately, you could do data['sample'] , but that syntax really exists more for allowing you to store property names in variables for retrieving data from objects.

Answer 2

Change method to type and console.log(data) to view the content of data passed to the callback function.

Also, add dataType: 'json' in the call.

$.ajax({
     url: 'example.com/something',
     type: 'GET',
     dataType: 'json',
     data: { 'sample':'test' },
     success: function(data, textStatus, jqXHR){
          console.log(data);  // will display the content of data 
     },
     error: function(a,b,c) {
          console.log('something went wrong:',a,b,c);
     }
});

Answer 3

Instead of this.data , in your case, to access the value "test", you'd need to use data.sample .

Try looking into JSON objects, as that is generally what AJAX requests will be returning. You're going to using "dot notation" a lot in JS.

Answer 4

What's your backend code? java c# php? if c# and mvc controller,you can defination an action the pramater in the action will be you ajax pass

Answer 5

  // want get data parameter // {'sample':'test'} 

Pass data as a property to jqxhr object at beforeSend , get object at success .

$.ajax({
  url: 'example.com/something',
  method: 'GET',
  data: {
    "sample": "test"
  },
  beforeSend: function(jqxhr, settings) {
    jqxhr._data = settings.url.split("?").pop();
  },
  success: function(data, textStatus, jqXHR) {
    // want get data parameter
    // {'sample':'test'}
    var _data = jqXHR._data.split("&").slice(0, 1).pop().split("=");
    var obj = {}; obj[_data[0]] = _data[1];
    console.log(_data, obj);
    // var obj = {}; 
    // someone answered that could get below code but I couldn't get it 
    // console.log(this.data);  => X 
  }
})

Answer 6

Other solution, you can put data into variable directly :

var dataObj = { 
  sample:'test' 
}; // => I want this data in success function.

$.ajax({
 url: 'example.com/something',
 method: 'GET',
 data: dataObj,
 success: function(response, textStatus, jqXHR){
      // then just console.log(dataObj.sample)
 }
});