python中的try-except方法出错

Question

I am having a problem with the try-except method i would like to monitor any errors in my script by sending those errors to my mail the script only checks file existence and it looks like:

def check_file_existence():
     try:
       with open('\\\\ntsrv1\\tohna\\SecurityTeam\\Varonis\\Varonis_monitoring_report\\Varonis_Action_Report.csv', 'r') as temp_file:
           temp_file.close()
     except ValueError as e:
         e = str(e)
         print(e)
         status_mail_notofication('error in move_report_to_folder_adding_date_to_file Function under varonis_report_analysis script  ','there was an error in check_file_existence Function','security88876@gmail.com')
         sys.exit(0)
     return

after running the code with purpose to get an error

i am getting this:

IOError: [Errno 2] No such file or directory: '\\\\ntsrv1\\tohna\\SecurityTeam\\Varonis\\Varonis_monitoring_report\\Varonis_Action_Report.csv'

and it doesn't go to the except part where i need to get the mail with the error ,it just stops

anyone know why?

TNX

Answer 1

except ValueError as e:
    print("ValueError caught: " + str(e))

Just catches exceptions of type ValueError . Exceptions tend to be derived from the Exception class, so this would catch any normal exception:

except Exception as e:
    print("Exception caught:" + str(e))

To be entirely sure you're catching everything, you can use:

except:
    print("Unknown exception caught")

Answer 2

也许使用except IOError as e:或简单地使用except:以确保它捕获错误