Php登录密码_verify

Question

I am learning how to use prepared statements and I thought I would try out a login system (simple) using the password_hash() and password_verify( ) functions. I have succesffuly inserted data in using prepared statemernts, now I wish to verify the password and do something with the user.

I seem to be getting back my fail message at this stage:

$stmt = $conn->prepare("SELECT username, password FROM users WHERE username = ?");
$stmt->bind_param('s', $username);

$username = $_POST['ulogin'];
$password = $_POST['upassword'];

$stmt->execute();
$stmt->bind_result($username, $password);



$row = $stmt->fetch();
if ($stmt->num_rows == 1) {
    if (password_verify($password, $row['user_password'])) {
        echo 'success';
    }
} else {
 echo "Wrong data";
}

$stmt->close();
$conn->close();

If I do a var_dump($stmt->fetch()); and the login username is correct is comes back as bool(true)

Im not sure how to attempt to verify the password now.

Answer 1

<?php

$stmt = $conn->prepare("SELECT username, password FROM users WHERE username = ?");
$stmt->bind_param('s', $username);

$username = $_POST['ulogin'];
$password = $_POST['upassword'];

$stmt->execute();
$stmt->bind_result($username, $password);
$row = $stmt->fetch(); //fetch DB results


if (!empty($row)) { // checks if the user actually exists(true/false returned)
    if (password_verify($_POST['upassword'], $row['password'])) {
        echo 'success'; // password_verify success!
    } else {
    echo 'failed';
    }
} else {
    echo "This user does not exist"; //email entered does not match any in DB
}

$stmt->close();
$conn->close();

You do not necessarilly need to check for number of rows. Also have an else statement if the password is not verified for any reason

Answer 2

This is one of your problems:

$password = $_POST['upassword'];
...
$stmt->bind_result($username, $password);
...
if (password_verify($password, $row['user_password'])) {

You are overwriting your $password variable so it is no longer the posted value.

Using the POST value should solve the problem:

 if (password_verify($_POST['upassword'], $row['user_password'])) {

or

 if (password_verify($_POST['upassword'], $password)) {

as you have bound the password from the result to that variable.

Also, if your username in the database is unique, you can replace:

$row = $stmt->fetch();
if ($stmt->num_rows == 1) {

with:

if ($row = $stmt->fetch()) {