delay_job传递实例方法和变量？

Question

I have a problem with getting application data from outside of self.method.

To useModel.delay.method, the method has to be a class one.

I really like that, it does all I need (like saving input parameters when calling method), but what I need to do is get variables from outside of method.

For example: User clicks button and starts the timer.

QuizzesController.delay(run_at: @quiz.time_limit.minutes.from_now).form_timeout(session[:user_id],session[:test_password])

Method form_timeout looks like this:

def self.form_timeout(id, test_password)
  if test_password == session[:test_password]
    Score.create(user_id: id, name: test_password, points: -1) 
    session.delete(:test_password)
  end
end

When I try to do that, I get an error "undefined method session" which means that I cannot reach that data when using self.method.

Any idea how to bypass that and let session[:test_password] (session has to pass most up-to-date information, because I compare session[:test_password] from time when timer has started (old one) and from time when it ends(new one)) like i did in self.method?

Answer 1

Any idea how to bypass that and let session[:test_password] ...

Nope, no way of doing that. session is not a simple instance methods. It gets data from cookies (by default). And cookies are inaccessible in a background worker context.

Rule of thumb for background workers is: delayed method must receive all data it needs in its parameters.