如何检查curl的http_code是否在200和299之间

Question

I would like to test a website until it returns with http_code between 200 and 299:

  until [[ $(curl --silent -o /dev/null -w %{http_code} -u admin:admin http://mywww:8080/api/v1) = "2[0-9][0-9]" ]] ;do
    printf '.'
    sleep 5
done

But it just keeps on looping even though curl returns 202 for example. I've tried substituting = with -eq when comparing to regex but then it throws an error

[[: 2[0-9][0-9]: syntax error: invalid arithmetic operator (error token is "[0-9][0-9]")

Answer 1

Try this:

until [[ $(curl -I --silent -o /dev/null -w %{http_code} -u admin:admin http://mywww:8080/api/v1) =~ 2[0-9][0-9]  ]] ;do
    printf '.'
    sleep 5
done

-I : Do a head instead of get. Much more efficent, if not blocked by the webserver.

=~ 2[0-9][0-9] : Equal Tilde operator that allows the use of regex in an if statement.

Side note: If you dont want to use equal tilde you should lose the qoutes on the pattern.