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json将单引号解析为javascript

[英]json parsing single quotes to javascript

hava php array something like this: 哈瓦PHP数组是这样的:

array(1) {
    [39]=>
    array(3) {
        [0]=>
        array(2) {
            ["id"]=>
            int(21)
            ["name"]=>
            string(14) "32''LE32HDF3010"
        },
        [1]=>
        array(2) {
            ["id"]=>
            int(22)
            ["name"]=>
            string(14) "40''LE40FHDE3010"
        },
        [2]=>
        array(2) {
            ["id"]=>
            int(23)
            ["name"]=>
            string(14) "40''40FS4610R"
        },

    }
}

and need to send this array to view like json_encode() but getting error like: Uncaught SyntaxError: missing ) after argument list 并且需要发送此数组以像json_encode()一样查看,但Uncaught SyntaxError: missing ) after argument list出现错误: Uncaught SyntaxError: missing ) after argument list

and when looking to error place it looks like this 当寻找错误的地方时,它看起来像这样 在此处输入图片说明

my php code looks like this: 我的PHP代码看起来像这样:

$phone_models = Phone_model::get() -> all();

$models = array();
foreach($phone_models as $model){
    $models[$model -> manufacturer_id][] = array(
        'id' => $model -> id,
        'name' => $model -> name,
    );
}

$models = json_encode($models);

And JS code: 和JS代码:

var models = $.parseJSON('{!!$models!!}');

As far as i know you can place the array inside JavaScript using json_encode() (see php.net ). 据我所知,您可以使用json_encode()将数组放入JavaScript中(请参阅php.net )。

Simply use something like the following PHP: 只需使用类似以下PHP的代码:

<?php
$array = ('foo', 'bar', array('foo', 'bar'))
?>

<script type="text/javascript">

var array = <?php echo json_encode($array); ?>

</script>

This prints the array into a script element. 这会将数组打印到脚本元素中。

Just do 做就是了

var models = <?php echo $models?>;

there is no need to parse the json if it is part of the html output/content. 如果json是html输出/内容的一部分,则无需解析json。

echo "var xyz = ".json_encode([1,2,3]).";";

becomes

var xyz = [1,2,3];

complementing @JustOneUnderMillions and @RemcovanOs answers, I made this PHPFiddle that shows an working example: 补充@JustOneUnderMillions和@RemcovanOs的答案,我制作了这个PHPFiddle,它显示了一个有效的示例:

http://phpfiddle.org/main/code/sm1x-zu6d http://phpfiddle.org/main/code/sm1x-zu6d

Code: 码:

<script>
    var json = 
<?php
class Model {
    function __construct($mi, $id, $name) {
        $this->manufacturer_id = $mi;
        $this->id = $id;
        $this->name = $name;    
    }
    public $manufacturer_id;
    public $id;
    public $name;
}

$pmodels = array(new Model(39, 21, "32''LE32HDF3010"), new Model(39, 22, "40''LE40FHDE3010"), new Model(39, 21, "40''40FS4610R"));
$models = array();

foreach($pmodels as $model){
    $models[$model -> manufacturer_id][] = array(
        'id' => $model -> id,
        'name' => $model -> name,
    );
}

$models = json_encode($models);


echo $models;        
?>;
    console.log(json);
</script>

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