makefile运行它编译的代码

Question

If I have a code that will run, call it main.cpp , and the executable is r.exe , then I write a makefile with the following target:

compile: 
    g++ -std=c++11 main.cpp -o r

The executable, r.exe takes as two arguments i.txt , o.txt . How do I add a second target to the makefile such that I can run the following command, and see the program execute:

make run i.txt o.txt

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I have tried adding a second target to the makefile:

run:
    r.exe $1 $2

for instance, but make declares: "'r' is up to date" and "nothing to be done for 'i.txt', ... etc."

I have also tried searching for a while now, but 'make', 'run' and 'variables' or 'arguments' have, essentially, a search firewall of unrelated content.

Answer 1

You can't pass arguments to make like that. The command make run i.txt o.txt would attempt to build the rules run , i.txt , and o.txt .

What you could instead to is use a variable:

run:
    r.exe ${ARGS}

make run ARGS="i.txt o.txt"

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Side-note, rules should make the files that they say they do. So you really would want your compile rule to look like:

r.exe : main.cpp
    g++ -std=c++11 $^ -o $@

compile : r.exe
.PHONY  : compile