为什么此c ++静态强制转换代码产生int而不是double

Question

Im new to C++ and i'm not sure why the output for this code is 8 and not 8.25?

can someone explain why this code outputs an int not a double?

Thanks :)

#include "stdafx.h"
#include <iostream>


int main()
{

double x = 8.25;
    int y;
    y = x;

    double z = static_cast<double>(y);
    std::cout << z << std::endl;
return 0;
}

Answer 1

The data is converted to the integer 8 in the statement y = x .

A static_cast cannot recover the lost ".25" after throwing it away by converting to int .