[英]How do you get the current figure number in Python's matplotlib?
I'm playing around with an example script that shows how to switch back and forth between figures. 我正在玩一个示例脚本,该脚本显示如何在数字之间来回切换。 I found the example here: http://matplotlib.org/examples/pylab_examples/multiple_figs_demo.html When I try to print out the figure number I get "Figure(640x480)" instead of the number 1 I was expecting. 我在这里找到了这个例子: http : //matplotlib.org/examples/pylab_examples/multiple_figs_demo.html当我尝试打印图号时,我得到“图(640x480)”而不是我期待的数字1。 How do you get the number? 你怎么得到这个号码?
# Working with multiple figure windows and subplots
import matplotlib.pyplot as plt
import numpy as np
t = np.arange(0.0, 2.0, 0.01)
s1 = np.sin(2*np.pi*t)
s2 = np.sin(4*np.pi*t)
plt.figure(1)
plt.subplot(211)
plt.plot(t, s1)
plt.subplot(212)
plt.plot(t, 2*s1)
plt.figure(2)
plt.plot(t, s2)
# now switch back to figure 1 and make some changes
plt.figure(1)
plt.subplot(211)
plt.plot(t, s2, 's')
ax = plt.gca()
ax.set_xticklabels([])
# Return a list of existing figure numbers.
print "Figure numbers are = " + str(plt.get_fignums())
print "current figure = " + str(plt.gcf())
print "current axes = " + str(plt.gca())
plt.show()
Here is the output: 这是输出:
Figure numbers are = [1, 2]
current figure = Figure(640x480)
current axes = Axes(0.125,0.53;0.775x0.35)
Figure
对象有一个number
属性,因此你可以通过它获得数字
>>> plt.gcf().number
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