Android Studio，共享首选项设置文本颜色

Question

At the moment I am trying to run this lines of code:

    @Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setTitle("Tell me");
    setContentView(R.layout.activity_post);
    getSupportActionBar().setDisplayHomeAsUpEnabled(true)
    ;
    editText = (EditText) findViewById(R.id.editText1);
    textView = (TextView) findViewById(R.id.textView);

    SharedPreferences sharedPreferences = PreferenceManager.getDefaultSharedPreferences(getApplicationContext());
    String s = sharedPreferences.getString("font_list", "null");
    Typeface face = Typeface.createFromAsset(getAssets(), "fonts/" + s);
    editText.setTypeface(face);

    String s2 = sharedPreferences.getString("font_size", "8");
    editText.setTextSize(Float.parseFloat(s2));

    String s3 = sharedPreferences.getString("font_color", "#000");
    editText.setTextColor(Color.parseColor(s3));



   // File directory = new File(path);
  // directory.mkdirs();
}

• I am trying to set and store the colors that user choices to allow them to type in that color, but whenever I try to run the app or do anything within the app, it crashes because of the setTextColor function and the sharePreferences within the string for it.

here is logcat image

Answer 1

As per you log cat image you have IllegalArgumentException exception

You have color string which is not in correct format see this Color.parseColor

Parse the color string, and return the corresponding color-int. If the string cannot be parsed, throws an IllegalArgumentException exception. Supported formats are: #RRGGBB #AARRGGBB or one of the following names: 'red', 'blue', 'green', 'black', 'white', 'gray', 'cyan', 'magenta', 'yellow', 'lightgray', 'darkgray', 'grey', 'lightgrey', 'darkgrey', 'aqua', 'fuchsia', 'lime', 'maroon', 'navy', 'olive', 'purple', 'silver', 'teal'.

Change

String s3 = sharedPreferences.getString("font_color", "#000");

to

String s3 = sharedPreferences.getString("font_color", "#000000");

Answer 2

String s3 = sharedPreferences.getString("font_color", "#000000");

This would be proper. Else use Color.NAME_OF_COLOR , many are covered here.

Answer 3

In Android You need to provide either 6 or 8 HexaColor code. As it supported RGB or ARGB. every two character define value of once color while making final color. Like:- #112233

11 define Red color with value 17 from (0 to 255 range)

22 define Green color with value 34 from (0 to 255 range)

33 define Blue color with value 51 from (0 to 255 range)

Same if you have alpha than define first two digit with alpha value:- Like with 50% opacity same above color HexaValue will be:- #80112233

where 80 is 128 alpha value from (0 to 255 range)

So correct solution for your problem will be:-

String s3 = sharedPreferences.getString("font_color", "#000000");

instead of

String s3 = sharedPreferences.getString("font_color", "#000");