在SQL Server中转换日期时间

Question

In SQL server, date is getting saved in the following format:-

2017-02-20 05:59:58.537

But I need the output in the following format:

20/Feb/2017 11:29:58 AM

Answer 1

尝试这个

select  replace(convert(varchar(11),GETDATE(),113), ' ', '/')+ ' '+    RIGHT(CONVERT(varchar(20), GETDATE(), 22), 11);

Answer 2

尝试这个，

SELECT replace(convert(NVARCHAR, getdate(), 106), ' ', '/')+' '+right(getdate(),7)

Answer 3

Try below conversion method :

 DECLARE @DATE DATETIME = '2017-02-20 05:59:58.537'
 SELECT REPLACE(CONVERT(VARCHAR(11),@DATE,113), ' ', '/') + ' ' 
 +CONVERT(VARCHAR(20),@DATE,108)+' ' +RIGHT(@DATE,2)

Answer 4

SQL stores the date as per the default setting (yyyy-mm-dd hh:mm:ss:ms). while fetching that date you need to convert that date according to your requirement.

Try this

Answer 5

正确答案：

SELECT REPLACE(CONVERT(VARCHAR(11), getdate(), 113), ' ', '/') + ' ' + CONVERT(VARCHAR(20), CONVERT(TIME, getdate()), 22)

Answer 6

I have a date Function I use, and you could modify it to include details for hours, minutes and seconds, too.

CREATE FUNCTION [dbo].[fn_DateDisplay]
(
    -- Add the parameters for the function here
    @dateIn date
)
RETURNS nvarchar(MAX)
AS
BEGIN
    -- Declare the return variable here
    DECLARE @dateOut nvarchar(MAX)

    DECLARE @yearIn int
    DECLARE @monthIn int
    DECLARE @dayIn int

    DECLARE @monthOut nvarchar(3)

    -- Add the T-SQL statements to compute the return value here
    SET @yearIn = YEAR ( @dateIn ) 
    SET @monthIn = MONTH ( @dateIn ) 
    SET @dayIn = DAY ( @dateIn ) 

    SET @monthOut = SUBSTRING ( DATENAME ( MONTH , @dateIn ) , 1 , 3 )

    SET @dateOut = CONCAT ( @dayIn , ' ' , @monthOut , ' ' , @yearIn )

    -- Return the result of the function
    RETURN @dateOut

END