如何使用Simple HTML DOM和cURL排除特定类别的孩子的抓取结果？

Question

I am scraping a certain website for specific links, which I am saving to my $url_results array. But want to exclude adding the link to the array if the li cluster, with the class of list-items__item , includes a child->child->child span with a class of list-items__item__notice .

Cluster I am scraping:

<li>
    <a href="" data-lpurl=""> <!--The href I am scraping-->
        <span class="list-items__item__position"></span>
        <div class="list-items__item__title">
            <span class="list-items__item__notice"> <!--I don't want to add to my array if this span is present-->
            </span>
        </div>
    </a>
</li>

My PHP scraping function:

$items = $html->find('li[class=list-items__item]');  
foreach($items as $post) {
    $url_results[] = $url . ($post->children(0)->href);
}

I am using Simple HTML DOM and cURL to scrape.

Answer 1

I solved the problem by adding an if-sentence, checking whether the tag was empty and if so, add the href to my array, if not, do nothing, as below:

foreach($items as $post) {
    if (empty($post->children(0)->children(1)->children(0)->plaintext)) {
        $url_results[] = $url . ($post->children(0)->href);
    }
    else {}
}