返回依赖于另一列中的值的值

Question

I thought this would be pretty easy but for some reason, I can't wrap my head around it. Maybe I am tired. Anyway, I want to return a policy value that has a status code of 1 and 4. I have a simple query:

select policiesid, eDeliveryStatusCd
from UserPolicyHistory
where PoliciesID is not null
and eDeliveryStatusCd in (1,4)
order by policiesid

Results:

See the highlighted policiesid of 10241? I want only those to return because it has an edeliverystatuscd of 1 and 4. So I want a policiesid that has a status code of 1 and 4 to return only, ignoring the rest. I thought it should be pretty simple. I don't know why but I can't figure it out today. Any help is appreciated!

Answer 1

Just add group by and having :

select policiesid
from UserPolicyHistory
where PoliciesID is not null and eDeliveryStatusCd in (1, 4)
group by policiesid
having count(distinct eDeliveryStatusCd) = 2;

Answer 2

The other answer works if the table is unique on policiesid, eDeliveryStatusCd. If not try:

select policiesid, count(*)
from (select distinct policiesid, eDeliveryStatusCd
    from UserPolicyHistory uph1
    where PoliciesID is not null
    and eDeliveryStatusCd in (1,4))
having count(*) > 2

Answer 3

using exists() :

select policiesid, eDeliveryStatusCd
from UserPolicyHistory as t
where PoliciesID is not null
  and eDeliveryStatusCd in (1,4)
  and exists (
    select 1
    from UserPolicyHistory as i
    where i.policiesid = t.policiesid
      and i.eDeliveryStatusCd in (1,4)
      and i.eDeliveryStatusCd <> t.eDeliveryStatusCd
  )
order by policiesid