Regex / preg_match-在字符串和电子邮件地址之间获取文本

Question

I'm extracting data from emails. I have pieces of text like this:

Eg. 1: some standard text.   Bugs Bunny bugs@gmail.com 0411111111 more standard text 
Eg. 2: some standard text.   Bugs The Bunny bugs@gmail.com 0411111111 more standard text
Eg. 3: some standard text.   Bugs Bunny bugs.bunny@gmail.com 0411111111 more standard text
Eg. 4: some standard text.   Bugs bugs.bunny@gmail.com +6141 111 111 more standard text

As you can see, there is a name, email and phone number that I want to extract. The email should be easy enough, and I'm sure I can work out the phone options but how could I get the name?

I know the logic is: get the text after some standard text. and before the the first non-space-separated string before the @ , but how?

This is my starting point (?<=some standard text. )(.*?)(?=@)

This gives me a result with a group (?<=some standard text. )(.*?)(?:[\\w-\\.]+)@ so I think I'm on the right path.

I'm using php.

Answer 1

Here is a quick version/example I came up with:

(?<=some standard text. )(.*?) ([^\s]+@[^\s]+) (\+?\d+(?:\s\d+)*) 

regex101.com/r/Wjz66g/1

It's not perfect, but it does follow along the same lines as what you were doing and might work enough.

Answer 2

I wrote this, you can test it on: https://regex101.com/r/A29hjE/8

(?x) # Here we are entering the the free space mode

# Here we assure the spaces are not matched by the `[\w ]+` group
(?:\.\s+)

# Here we are matching for the guys name, before its email address
([\w ]+(?:\w+))\s+

# Here we match the email
(\w[^\s]+@[^\s]+)\s+

# Here  we match the telephone number
(\+?[\d ]+)(?!\w)