Unix，如何在双引号之间提取值

Question

I have some VBA macros, and I need to translate all output messages, but these messages are enclosed between double quotes, like this:

If Not IsNumeric(Sheet28.Range("I9")) Then
   Call MsgBox("Error! Voucher expiry years must be a number", vbDefaultButton1 Or vbExclamation, "Error!")
   Application.Undo
End If

And I want this:

"I9"
"Error! Voucher expiry years must be a number"
"Error!"

Is it possible to do it with grep, sed, awk, regex or something else?

"I9" is not a message, but I'll take care of removing texts that are not messages, removing duplicates, etc.

Thanks in advance!

Answer 1

You'll likely want a pattern such as:

"[^"]+"             # matches I9 also
"[^)I"]+"           # won't match messages starting with "I"
"[^"]+?"            # lazy match in case you aren't using grep, egrep, etc.
"[^"][^0-9(]+"      # won't match messages with the second character as digit.

Using grep or egrep :

grep -Eo '"[^"]+"'
egrep -o '"[^"]+"'

Would match "I9" , "Error!" , "Error! Voucher expiry years must be a number "

grep -Eo '"[^"][^0-9(]+"' 

Matches "Error!" , "Error! Voucher expiry years must be a number" , "I match also"

• " matches the character " literally (case sensitive)
• Match a single character not present in [^I)"]
• +? Quantifier — Matches between one and unlimited times, as few times as possible, expanding as needed (lazy)

Example :

https://regex101.com/r/z2eSQF/2