如何在vim命令中使用正则表达式格式化电话号码列表？

Question

Given the following list of phone numbers

8144658695
812 673 5748
812 453 6783
812-348-7584
(617) 536 6584
834-674-8595

Write a single regular expression (use vim on loki) to reformat the numbers so they look like this

814 465 8695
812 673 5748
812 453 6783
812 348 7584
617 536 6584
834 674 8595

I am using the search and replace command. My regular expression using back referencing:

:%s/\(\d\d\d\)\(\d\d\d\)\(\d\d\d\d\)/\1 \2 \3\g 

only formats the first line. Any ideas?

Answer 1

尝试这个：

:%s,.*\(\d\d\d\).*\(\d\d\d\).*\(\d\d\d\d\).*,\1 \2 \3,

Answer 2

First use count to match a pattern multiple times, it is a bad habbit to repeat the pattern:

\d\{3} "instead of \d\d\d

Than you also have to match the whitespaces etc:

:%s/.*\(\d\{3}\).*\(\d\{3}\).*\(\d\{4}\).*/\1 \2 \3/g 

Or even better, escape the whole regex with \\v :

:%s/\v.*(\d{3}).*(\d{3}).*(\d{4}).*/\1 \2 \3/g

This greatly increases readability