[英]Save Multiple Dropdowns Selections from a Table - PHP MySQL
I have a Table with a column with Drop-down Selections. 我有一个带有下拉菜单的列的表。 How do I save the selected choices on Save Button Click to my database. 如何将“保存”按钮上的选定选项保存到我的数据库中。
I tried the following but I cant seem to get any data into the Array : 我尝试了以下操作,但似乎无法将任何数据放入Array中:
TABLE DISPLAY 桌子展示
DROPDOWN IN TABLE : 表中的下拉列表:
<td width="10%" nowrap>
<select class="bs-select form-control" name="providers[]" id="serviceProviders" data-id="<?php echo $row["provider_id"]; ?>" id="serviceProvider" data-live-search="true" data-size="8">
</select>
JAVASCRIPT PART Java脚本部分
$(document).on('click', '#saveChanges', function(e){
var id = [];
$('serviceProviders').each(function(i){
id[i] = $(this).val();
console.log('Service Provider Values are = ' + id[i]);
});
if(id.length === 0) //tell you if the array is empty
{
alert("Please Select at least one transaction");
}
else
{
$.ajax({
url:'some_php_scrip_to_save_the_data.php',
method:'POST',
data:{id:id},
success:function()
{
for(var i=0; i<id.length; i++)
{
// $('tr#'+id[i]+'').css('background-color', '#ccc');
// $('tr#'+id[i]+'').fadeOut('slow');
window.location.reload(true);
}
}
});
}
});
The ID attribute of an element must be unique. 元素的ID属性必须是唯一的。 $('serviceProviders') should return you only one select element. $('serviceProviders')应该只返回一个选择元素。 Try suffixing the column number to the id inorder to make it unique. 请尝试在ID后面加上列号,以使其唯一。
var id = [] for (var i = 1; i <= MaxColNo; i++) { var e = document.getElementById("serviceprovider" + i); var text = e.options[e.selectedIndex].text; id[i] = text; }
And in ajax call surround property name with quotes - data :{'id':id} 在ajax中,用引号引起来的环绕属性名称-data:{'id':id}
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