在while循环中使用raw_input并将其分配给变量？

Question

is42= False
while(raw_input()):
    d = _
    if d == 42:
      is42 = True
    if not is42:
      print d

for this python block of code I want to use outside of the interactive prompt mode. So I can't use _ as the last output. How do I assign raw_input to a variable? I'm doing an exercise off a site. about 5 values is the input and I'm suppose to spit some output out for each corresponding input value. What's the best way to take in this input to do that?

Answer 1

This appears to be very inefficient logic. Do you really need the is42 status flag as well? If not, you might want something like

stuff = raw_input()
while stuff:
    if stuff != "42":
         print stuff
    stuff = raw_input()

Does that fix enough of your troubles?

Answer 2

is42=False
while(!is42):
    d = int(raw_input("Enter a number: "))
    is42 = d==42
    print "d = ", d

That should do it if I understand the requirements of your problem correctly.

Answer 3

Hi and welcome to Python!

The raw_input() function returns the input read as a string. So where you have d = _ , you can replace that with d = raw_input() . A question I have for you is why you had it inside the while condition? If you wanted it to keep asking the user for a number over and over, then replace while(raw_input()): with while True: .

One more thing, raw_input() always returns a string. So if you run print '30' == 30 , you'll see that a string representation of 30 is not equal to the number representation of 30. But that's not a problem! You can turn the return value of raw_input() into an integer type by replacing d = raw_input() with d = int(raw_input()) .

Now there will be another problem when the user gives you an input that can't be converted to an integer, but handling that can be an exercise for you. :)

Final code:

is42= False
while True:
    d = int(raw_input())
    if d == 42:
      is42 = True
    if not is42:
      print d