如果包含键值对，则返回数组中的对象

Question

How do you return objects in an array if it contain specific key-value pairs?

I need to return it if it has all key value pairs given, not just one.

for example,

This function with the array of objects as the 1st argument, and an object with given key value pairs as the 2nd argument

whatIsInAName([{ "a": 1, "b": 2 }, { "a": 1 }, { "a": 1, "b": 2, "c": 2 }], { "a": 1, "b": 2 }); 

should return

[{ "a": 1, "b": 2 }, { "a": 1, "b": 2, "c": 2 }]

Answer 1

You can do this with filter() and every() .

 function whatIsInAName(a, b) { return a.filter(function(e) { return Object.keys(b).every(function(c) { return e[c] == b[c] }) }) } console.log(whatIsInAName([{ "a": 1, "b": 2 }, { "a": 1 }, { "a": 1, "b": 2, "c": 2 }], { "a": 1, "b": 2 })) 

Answer 2

Use underscore.js . It's simple.

 function whatIsInAName(a, b){ return _.where(a, b); } var data = whatIsInAName([{ "a": 1, "b": 2 }, { "a": 1 }, { "a": 1, "b": 2, "c": 2 }], { "a": 1, "b": 2 }); console.log(data); 

 <script src="https://cdnjs.cloudflare.com/ajax/libs/underscore.js/1.8.3/underscore-min.js"></script> 

Answer 3

Use Array#filter method with Array#every method.

 function whatIsInAName(arr, obj) { // get the keys array var keys = Object.keys(obj); // iterate over the array return arr.filter(function(o) { // iterate over the key array and check every property // is present in the object with the same value return keys.every(function(k) { return obj[k] === o[k]; }) }) } console.log(whatIsInAName([{ "a": 1, "b": 2 }, { "a": 1 }, { "a": 1, "b": 2, "c": 2 }], { "a": 1, "b": 2 })); 

Answer 4

You could filter the array with a check for the pattern's key and values.

 function whatIsInAName(array, pattern) { var keys = Object.keys(pattern); return array.filter(function (o) { return keys.every(function (k) { return pattern[k] === o[k]; }); }); } console.log(whatIsInAName([{ "a": 1, "b": 2 }, { "a": 1 }, { "a": 1, "b": 2, "c": 2 }], { "a": 1, "b": 2 }));