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TypeScript:如何在编译时声明固定大小的数组以进行类型检查

[英]TypeScript: how to declare array of fixed size for type checking at Compile Time

Update : These checks are meant for compile time , not at runtime . 更新 :这些检查用于编译时 ,而不是在运行时 In my example, the failed cases are all caught at compile time, and I'm expecting similar behaviour for the other should-fail cases. 在我的例子中,失败的案例都是在编译时捕获的,我期待其他应该失败的情况下的类似行为。

Suppose I'm writing a table-like class where I want all members of the class to be arrays of the same length, something like: 假设我正在编写一个类似于表的类,我希望该类的所有成员都是相同长度的数组,如:

class MyClass {
  tableHead:  string[3]; // expect to be a 3 element array of strings
  tableCells: number[3]; // expect to be a 3 element array of numbers
}

The closest solution I've found so far is: 到目前为止我找到的最接近的解决方案是:

class MyClass {
  tableHead:  [string, string, string];
  tableCells: [number, number, number];
}

let bar = new MyClass();
bar.tableHead = ['a', 'b', 'c']; // pass
bar.tableHead = ['a', 'b'];      // fail
bar.tableHead = ['a', 'b', 1];   // fail

// BUT these also pass, which are expected to fail at compile time
bar.tableHead = ['a', 'b', 'c', 'd', 'e']; // pass
bar.push('d'); // pass
bar.push('e'); // pass

Any better ideas? 有更好的想法吗?

Update 2: From version 3.4, what the OP asked for is now fully possible with a succinct syntax ( Playground link ): 更新2:从版本3.4开始,OP所要求的内容现在完全可以使用简洁的语法( Playground链接 ):

class MyClass {
  tableHead: readonly [string, string, string]
  tableCells: readonly [number, number, number]
}

Update 1: From version 2.7, TypeScript can now distinguish between lists of different sizes . 更新1:从版本2.7开始,TypeScript现在可以区分不同大小的列表

I don't think it's possible to type-check the length of a tuple. 我不认为可以输入 - 检查元组的长度。 Here 's the opinion of TypeScript's author on this subject. 以下是TypeScript作者对此主题的看法。

I'd argue that what you're asking for is not necessary. 我认为你所要求的并不是必需的。 Suppose you define this type 假设您定义了此类型

type StringTriplet = [string, string, string]

and define a variable of that type: 并定义该类型的变量:

const a: StringTriplet = ['a', 'b', 'c']

You can't get more variables out of that triplet eg 你不能从那个三元组中获得更多的变量,例如

const [one, two, three, four] = a;

will give an error whereas this doesn't as expected: 会出错,而这不符合预期:

const [one, two, three] = a;

The only situation where I think the lack of ability to constrain the length becomes a problem is eg when you map over the triplet 我认为缺乏约束长度的能力成为问题的唯一情况是例如当你map三元组时

const result = a.map(/* some pure function */)

and expect that result have 3 elements when in fact it can have more than 3. However, in this case, you are treating a as a collection instead of a tuple anyway so that's not a correct use case for the tuple syntax. 并且期望result有3个元素,实际上它可以有3个以上。但是,在这种情况下,你无论如何都将a视为集合而不是元组,因此这不是元组语法的正确用例。

Here is a simple example of a class to control the length of its internal array. 下面是一个控制其内部数组长度的类的简单示例。 It isn't fool-proof (when getting/setting you may want to consider whether you are shallow/deep cloning etc: 这不是万无一失的(在获取/设置时你可能想要考虑你是浅层/深层克隆等:

https://jsfiddle.net/904d9jhc/ https://jsfiddle.net/904d9jhc/

class ControlledArray {

  constructor(num) {
    this.a = Array(num).fill(0); // Creates new array and fills it with zeros
  }

  set(arr) {
    if (!(arr instanceof Array) || arr.length != this.a.length) {
      return false;
    }
    this.a = arr.slice();
    return true;
  }

  get() {
    return this.a.slice();
  }

}

$( document ).ready(function($) {

  var m = new ControlledArray(3);

  alert(m.set('vera')); // fail
  alert(m.set(['vera', 'chuck', 'dave'])); // pass

  alert(m.get()); // gets copy of controlled array

});

From Typescript: Can I define an n-length tuple type? 来自Typescript:我可以定义一个n长度的元组类型吗? , programmatically, with dynamic length: ,以编程方式,具有动态长度:

type Tuple<TItem, TLength extends number> = [TItem, ...TItem[]] & { length: TLength };

type Tuple9<T> = Tuple<T, 9>;

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