[英]BASH/Linux - Finding the next date from a variable
In my Unix shell programming, I am trying to get the next date (tomorrow's date) over a reference date defined as "a". 在我的Unix Shell编程中,我试图获取定义为“ a”的参考日期后的下一个日期(明天的日期)。 Here is the code:
这是代码:
a=2016-01-02
Which operator would I use in my code so that Unix will automatically define a as tomorrow's date as in below 我将在代码中使用哪个运算符,以便Unix将如下所示自动定义为明天的日期
a=2016-01-03
date
has a -d
option that is very useful in this situation. date
具有-d
选项,在这种情况下非常有用。
To get the next day, add a space after the date then add 1 day
要获得第二天,请在日期之后添加一个空格,然后添加
1 day
date +%Y-%m-%d -d "$a 1 day"
It's important to add the format specifier because without it, you would get the following output 添加格式说明符很重要,因为没有它,您将得到以下输出
=>"Sun Jan 3 00:00:00 UTC 2016"
To update the a
variable, you could do something like this 要更新的
a
变量,你可以做这样的事情
a=$(date +%Y-%m-%d -d "$a 1 day")
Remember to wrap the command inside of parentheses with a $
sign in front of it. 请记住,将命令包装在括号内,并在其前面加一个
$
号。
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