Lodash不执行嵌套方法，

Question

given this array var array = [{a:1, b: 2, c: 3}, {a: 2, b: 4, c: 4}] .

I want to iterate through each item in the array and omit the key c and it's value using lodash.

here is the method I tried

_.each(array, function (obj) { return _.omit(obj, ['a']); });

Expected Output should be // [{b: 2, c: 3}, {b: 4, c: 4} ] but lodash returns the original array // [{a:1, b: 2, c: 3}, {a: 2, b: 4, c: 4}]

Answer 1

Instead of forEach() to return new modified array you should use map() , also first parameter is array.

 var array = [{a:1, b: 2, c: 3}, {a: 2, b: 4, c: 4}] var result = _.map(array, function (obj) { return _.omit(obj, ['a']); }); console.log(JSON.stringify(result, 0, 4)) 

 <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.15.0/lodash.min.js"></script> 

Answer 2

A probably-not-the-lo-dash-iest way of handling it (assuming you actually want to omit a ):

_.each(lnkn, function (obj) {
    var returnObj = {};
    for (prop in obj) {
        if (obj.hasOwnProperty(prop) {
            if (prop !== 'a') {
                returnObj[prop] = obj[prop];
            }
        }
    }
    return returnObj;
});

Answer 3

_.forEach is supposed to return the original array. You re looking for _.map .

 const array = [{a:1, b: 2, c: 3}, {a: 2, b: 4, c: 4}]; const result = _.map(array, obj => _.omit(obj, 'a')); console.log(result); 

 <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.js"></script> 

Or you can modify the objects in place:

 const array = [{a:1, b: 2, c: 3}, {a: 2, b: 4, c: 4}]; _.forEach(array, obj => { delete obj.a; }); console.log(array); 

 <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.js"></script>