[英]C# converting an array returned as a generic object to a different underlying type
I have a C# method which uses object
as a generic container to return a data array which could be declared using different data types. 我有一个C#方法,它使用
object
作为通用容器来返回一个可以使用不同数据类型声明的数据数组。 Below a simplified example of such a method: 下面是这种方法的简化示例:
void GetChannelData(string name, out object data)
{
// Depending on "name", the underlying type of
// "data" can be different: int[], byte[], float[]...
// Below I simply return int[] for the sake of example
int[] intArray = { 0, 1, 2, 3, 4, 5 };
data = intArray;
}
I need to convert all the returned array elements to double
but so far I could not find a way. 我需要将所有返回的数组元素转换为
double
但到目前为止我找不到方法。 Ideally I would like to perform something like: 理想情况下,我想执行以下操作:
object objArray;
GetChannelData("test", out objArray);
double[] doubleArray = Array.ConvertAll<objArray.GetType().GetElementType(), double>(objArray, item => (double)item);
Which miserably fails because ConvertAll
does not accept types defined at runtime. 由于
ConvertAll
不接受在运行时定义的类型,因此失败了。 I have also tried intermediate conversions to a dynamic
variable, to no avail. 我也尝试过中间转换为
dynamic
变量,但无济于事。
Is there any way to perform such type conversion in a simple manner? 有没有办法以简单的方式执行这种类型转换?
If you don't know the type at compile time you can try to convert it. 如果您在编译时不知道类型,可以尝试转换它。
var array = (IEnumerable)objArray;
var doubles = array.OfType<object>().Select(a => Convert.ToDouble(a)).ToArray();
If you don't know the type of array elements at compile-time: 如果在编译时不知道数组元素的类型:
var doubleArray = (objArray as Array).OfType<object>()
.Select(m => Convert.ToDouble(m)).ToArray();
u can create extension method.. 你可以创建扩展方法..
public static IEnumerable<T> Convert<T>(this IEnumerable source)
{
foreach (var item in source)
yield return (T)System.Convert.ChangeType(item, typeof(T));
}
using .. 用...
object objArray;
GetChannelData("test", out objArray);
var array = (IEnumerable)objArray;
var doubleArray = array.Convert<double>().ToArray();
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