[英]What is type variable in java -(number)d
I can't cast this value as Integer
and I can't file what type is (I know is String
) but I need convert as number, Interger.parse()
does not work I get Exception
. 我不能将此值转换为
Integer
,也无法归档什么类型(我知道是String
),但是我需要将其转换为数字, Interger.parse()
不能正常工作,我会得到Exception
。
String str = "-10d";
Interger.parse(str); //I get Exception
String str = "-10b"
(mentioned in question) or "-10d" (mentioned in title)? String str = "-10b"
(有问题)或“ -10d”(有标题)?
If what you mean is -(number)d,then it is double. 如果您的意思是-(number)d,则为两倍。
try 尝试
double b = Double.parseDouble("-10d");
instead of using Integer.parseInt
而不是使用
Integer.parseInt
You can use this to convert your String
to int
. 您可以使用此方法将
String
转换为int
。
String str = "-10d";
int i = Double.valueOf(str).intValue();
Hope this helps! 希望这可以帮助!
Here you get the double
value: 在这里,您获得了
double
值:
String str = "-10d";
Double d = Double.parseDouble(str);
System.out.println(d);
And to get the integer value: 并获得整数值:
int intValue = d.intValue();
Other solutions, which change the input string
for the parse
method are (I don't recommend them): 其他解决方案会更改
parse
方法的输入string
(我不建议这样做):
int x = Integer.valueOf(str.substring(0, str.length() - 1));
int y = Integer.valueOf(str.replace('d', ' ').trim());
You get Exception because it is not correct there are no Interger.parse(str);
您会收到Exception,因为它不正确,没有
Interger.parse(str);
i think you want to make : 我想你想做:
Integer.parseInt(str);
But your string have d
and d work with Double not with Integer so instead use this : 但是您的字符串中的
d
和d与Double一起使用而不与Integer一起使用,因此请使用以下命令:
String str = "-10d";
Double.parseDouble(str);
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