无法在Python中解压缩文件夹

Question

I tried unzipping a file through Python using zipfile.extractAll but it gave BAD zip file, hence I tried this:

zipfile cant handle some type of zip data?

As mentioned in this answer, i used the code:

def fixBadZipfile(zipFile):  
     f = open(zipFile, 'r+b')  
     data = f.read()  
     pos = data.find('\x50\x4b\x05\x06') # End of central directory signature  
     if (pos > 0):  
         self._log("Truncating file at location " + str(pos + 22) + ".")  
         f.seek(pos + 22)   # size of 'ZIP end of central directory record' 
         f.truncate()  
         f.close()  
     else:  
         # raise error, file is truncated  enter code here

but it gave the error

Message File Name Line Position Traceback
C:\\Users\\aditya1.r\\Desktop\\Python_pyscripter\\module1.py 50
main C:\\Users\\aditya1.r\\Desktop\\Python_pyscripter\\module1.py 17
fixBadZipfile C:\\Users\\aditya1.r\\Desktop\\Python_pyscripter\\module1.py 37
TypeError: 'str' does not support the buffer interface

I'm using Python 3.4

How can i unzip this file?

Answer 1

please go through this link this might be what you are looking for

Unzipping files in python

Answer 2

You are reading the file as a bytes object but trying to find passing a string object so just simply change this line -

pos = data.find('\x50\x4b\x05\x06')

to

pos = data.find(b'\x50\x4b\x05\x06') 

Note that I have casted it to a byte object by simply prepending a b .

You don't need to do this is Python 2.X but in python 3.X you need to explicitly serialize a string object to a byte object.

Answer 3

import subprocess

subprocess.Popen('unzip ' + file_name, shell = True).wait()

Hope this help you :)