sed提取字符串中的子字符串和子字符串的首次出现之间的模式-获取相对路径

Question

I have the following line:

SF:/Users/someuser/Documents/workspace/project/src/app/somejavascriptfile.js ./coverage/coveragereport.info

I am trying to get the relative path from the above absolute path using sed in bash.

Tried a bunch of combinations but none of the regexes seem to work appropriately.

This is what I tried:

ABSOLUTEPATH=SF:$(echo $PWD | sed 's_/_\\/_g')
sed -i '' 's/.*'$ABSOLUTEPATH'/SF:' ./coverage/coveragereport.info

but this doesn't work as intended.

Any idea?

Answer 1

Why not do it directly, without having to use an intermediate variable:

sed -E -i '' "s@(SF:)$PWD@\1@" ./coverage/coveragereport.info

or

sed -i '' "s@SF:$PWD@SF:@" ./coverage/coveragereport.info

---

What you are doing right now is fine, except that it needs a / at the end of sed expression:

ABSOLUTEPATH=SF:$(echo $PWD | sed 's_/_\\/_g')
sed -i '' 's/.*'$ABSOLUTEPATH'/SF:/' ./coverage/coveragereport.info