jq-如何在shell脚本中转​​义'*'（特殊字符）？

Question

Im using the following command in shell script

echo $(jq -n '"1\n2\n3" | gsub("\n"; @t " * ")')

and the expected output is

"1 * 2 * 3" 

But in shell script it replaces '\\n' with all the file names in the respective directory (ie '*' is treated as a special parameter in this context).

1 file1 file2 2 file1 file2 3

When we execute the same in a terminal it gives the expected output.

Can anyone help me in this?

Answer 1

You need to quote the command substitution to prevent the result ( 1 * 2 * 3 ) from undergoing pathname expansion.

echo "$(jq -n '"1\n2\n3" | gsub("\n"; @t " * ")')"

Keep in mind, though, that there is no reason capture the output of a command if the only thing you do with it is pass it as the lone argument to echo . Just let the command run by itself.

$ echo "$(jq -n '"1\n2\n3" | gsub("\n"; @t " * ")')"
"1 * 2 * 3"
$ jq -n '"1\n2\n3" | gsub("\n"; @t " * ")'
"1 * 2 * 3"

(As a bonus, jq will probably produce colored output if you aren't capturing the output.)