JS-遍历数组并为if语句添加新的数字

Question

Lets assume I got some king of array... or for simplicity links.

HTML:

<a href'myspecialPath'></a>
<a href'myspecialPath'></a>
<a href'otherPath'></a>
<a href'otherPath'></a>
<a href'myspecialPath'></a>
<a href'myspecialPath'></a>

JS:

var test = document.getElementsByTagName('a');
var testLength = test.length;

for (i=0; i<testLength; i++){
    if (test.getAttribute('href').indexOf('myspecialPath') !== -1){
        //we list here every link with special patch
        // and I want it to have new numeration, not:
        link[i] have myspecialPath! // 1,2,5,6
        // cause it has gaps if link don't have special path - 1,2,5,6
        // and I want it to have numeric like 1,2,3,4
    }
else{
        link[i] without myspecialPath! // 3,4... and I want 1,2
    }
}

I hope everything is clear. I want to number link following from 1 [i+1] to the end without gaps.

EDIT: I did try [y+1] before but thanks to @American Slime the answer is:

y = 0;
for (i=0; i<testLength; i++){
        if (test.getAttribute('href').indexOf('myspecialPath') !== -1){
            links:[y ++] have myspecialPath! // 1,2,3,4... and so on, OK - it's working fine!
        }
    }

anybody fell free to correct this question/answer to better describe the problem.

Answer 1

I'm pretty sure this is what you're asking...

var links = document.querySelectorAll('a');
var count = 1;

for (var i = 0; i <= links.length-1; i++) {

    if (links[i].getAttribute('href') === 'myspecialPath') {

        links[i].setAttribute('href', 'myspecialPath' + count);
        count++;

    };

};

Answer 2

I assume what you want is an array of myspecialPath links and another of other links. You can use Array.prototype.push which doesn't care about the index like this:

var test = document.getElementsByTagName('a');
var testLength = test.length;

var specialLinks = [];
var otherLinks = [];

for (i=0; i<testLength; i++){
    // it should be test[i] not test
    if (test[i].indexOf('myspecialPath') !== -1){
        specialLinks.push(test[i]);
    }
    else{
        otherLinks.push(test[i]);
    }
}