[英]Unexpected token in JSON at position 43
Im trying to Fetch Data From a PHP Server Running MySQL. 我试图从运行MySQL的PHP服务器中获取数据。 In my angular controller I do
$http.get("dbconnection.php")
在我的角度控制器中,我执行
$http.get("dbconnection.php")
In my dbconnection.php I have this code which just Selects everything from the database and sends it back. 在我的dbconnection.php中,我有这段代码,该代码仅从数据库中选择所有内容并将其发送回去。
$conn = new mysqli......
$result = $conn->query("SELECT * FROM ...");
$outp = "";
while ($rs = $result->fetch_array(MYSQLI_ASSOC)) {
if ($outp != "") {
$outp .= ",";
}
$outp .= '{"id":"' . $rs["id"] . '",';
$outp .= '"name":"' . $rs["name"] . '",';
$outp .= '"price":"' . $rs["price"] . '"}';
$outp .= '"created":"' . $rs["created"] . '"}';
$outp .= '"img":"' . $rs["img"] . '"}';
}
$outp = '{"records":[' . $outp . ']}';
$conn->close();
echo $outp;
When I visit my site to see take a look at the Data under 当我访问我的网站以查看下面的数据时
Network Tab > XHR > dbconnection.php > Preview
I see the data but its weird formatted. 我看到了数据,但格式很奇怪。
See picture of weird formatted json 查看奇怪格式的json图片
I think thats the reason for why I get the 我认为这就是为什么我得到
Unexpected token in JSON at position 43
ERROR when I am trying to fetch the data. 当我尝试获取数据时
Unexpected token in JSON at position 43
错误。
To got well formatted JSON outputs, use json_encode
function. 要获得格式良好的JSON输出,请使用
json_encode
函数。
In your case : 在您的情况下:
$conn = new mysqli......
$result = $conn->query("SELECT * FROM ...");
$json = ["records" => []];
while ($rs = $result->fetch_array(MYSQLI_ASSOC)) {
$json["records"][] = $rs;
}
$conn->close();
echo json_encode($json);
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