Spring Data JPA，本机查询，返回错误的字段类型

Question

I have following native query method in my repository:

@Query(value="SELECT appSub.ApplicationFormId as appFormId, appSub.profileId as profileId, "
                + "p.CASId as profileCASId, ps.programId as programId FROM [unicas_config].[dbo].ApplicationFormEarlyDecisionConfig appFormED "
                + "INNER JOIN [unicas_ux].[dbo].ApplicationSubmission appSub ON appFormED.ApplicationFormId = appSub.applicationFormId "
                + "INNER JOIN [unicas_ux].[dbo].Profile p ON appSub.profileId = p.id "
                + "INNER JOIN [unicas_ux].[dbo].ProgramSelected ps ON p.id=ps.ProfileId AND appSub.applicationFormId = ps.instanceId "
                + "WHERE appFormED.EarlyDecisionVerdictDate >=:fromDate AND appFormED.EarlyDecisionVerdictDate <:toDate "
                + "AND appSub.EarlyDecisionStatus='Applied Early Decision' "
                + "AND appSub.ApplicationStatus='Received' "
                + "AND ps.IsPaid =1 "
                + "ORDER BY appSub.ApplicationFormId",nativeQuery = true)
List<Object[]> getAllEarlyDecisionApplicantsWithPaidProgramsOnVerdictDate(@Param("fromDate") Date fromDate, @Param("toDate") Date toDate);

Now, I want to map the returned result:

long appFormId = (Long)obj[0]
long profileId = (Long)obj[1]
long programId = (Long)obj[3]

When I am doing that, I am getting java.lang.ClassCastException: java.lang.Integer cannot be cast to java.lang.Long as Hibernate consider these ids of Integer type instead of Long .

Please, tell me how could I programatically tell Hibernate to return proper type.

Answer 1

To be on the safe side, I always cast numeric types to Number and then get the value of desired type from it, as JDBC driver can return Integer , Long , BigDecimal , etc. depending on the type of the database column:

((Number) obj[0]).longValue()

Of course, don't forget to check for null if column is nullable.