比较数据以显示彼此相差1000的结果

Question

I currently have a sample table as below:

  Country | Sessions US 1000 UK 500 US 2000 BR 7000 CA 3000 

The MySQL query I am looking help with is to get the output as follows, that displays the country name pairs that are within '1000' of each other

Sample Output:

  Country_A | Country_B US UK UK US US CA CA US 

Thanks for your help!

Answer 1

SELECT a.Country AS Country_A
     , b.Country AS Country_B
  FROM my_table a
  JOIN my_table b ON ABS(a.Sessions - b.Sessions) <= 1000
   AND a.Country <> b.Country;