[英]listagg Oracle SQL Query, join on same table
For every dog, I'd like to find the matching names of other animals besides dog, and add them in a comma-separated list. 对于每条狗,我都希望找到除狗以外的其他动物的匹配名称,并将它们添加到以逗号分隔的列表中。 Images of table and desired results of query below:
表的图像和查询的期望结果如下:
A table exists with this structure: 存在具有以下结构的表:
And I would like to create a query with results such as: 我想创建一个查询,其结果如下:
You can use a self-join
and then a listagg
. 您可以使用
self-join
,然后使用listagg
。
select tdog.animal,tdog.name
,listagg(tother.animal||'-'||tother.name||'-'||tother.id) within group(order by tother.id)
from tablename tdog
join tablename tother on tdog.name=tother.name and tdog.animal='dog' and tother.animal <> 'dog'
group by tdog.animal,tdog.name
With some tricks, you don't need a self join
: 使用一些技巧,您不需要
self join
:
select 'dog' as animal, name,
listagg(case when animal <> 'dog' then animal || '-' || name || '-' || id
end), ',') within group (order by id) as animals
from t
group by name
having sum(case when animal = 'dog' then 1 else 0 end) > 0
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