接下来如何输出？

Question

'#include <stdio.h>
int main() 
{ 
    short arr[3][2]={3, 6, 9, 12, 15, 18}; 
    printf("%d  %d", *(arr + 1)[1], **(arr + 2)); 
}'

The output of the program is 15,15?

Answer 1

As per the operator precedence rule *(a+i)[j] will be parsed as *((a + i)[j]) which is ultimately equivalent to *( *(a + i + j) ) . So for i = 1 and j = 1 it will be *( *(a + 1 + 1) ) = *( *( a + 2) + 0) = a[2][0]

Answer 2

In the image given, It has a 3*2 matrix ie 3 rows and two 2 rows.

*(arr+1)[1] can be interpreted like this:

arr+1 gives the address of 2nd row 1st element.

(arr+1)[1] gives the address of 3rd row 1st element.

*(arr+1)[1] gives the value present at this address

Following is the example:

void main(){
  short arr[3][2]={3,6,9,12,15,18};
  printf("%d %d %d %d", (arr ),(arr+1),(arr+1)[1],(arr +2));
}

Output:

-977229152 -977229148 -977229144 -977229144