[英]Java method signature compatibility
I have this sample code showing different method signatures: 我有这个示例代码显示不同的方法签名:
public class Main {
public static interface MyMap extends Map {}
public void func1(List<MyMap> m) {}
public void func2(List<Map> m) {}
public void func3(List<? extends Map> m) {}
public void func4(List<? extends Map<?, ?>> m) {}
public <M extends Map<?, ?>> void func5(List<M> m) {}
public static void main(String[] args) {
List<MyMap> myMap = null;
Main main = new Main();
main.func1(myMap); // OK
main.func2(myMap); // not applicable
main.func3(myMap); // OK
main.func4(myMap); // not applicable
main.func5(myMap); // OK
}
}
When I have MyMap
extending the raw type Map
I have these confusions about method signature compatibility in Java. 当我让MyMap
扩展原始类型Map
我对Java中的方法签名兼容性有这些困惑。
As seen func1
is a control test, obviously IDE will not complain. 如图所示func1
是一个控制测试,显然IDE不会抱怨。 In func2
, I can understand MyMap
is not exactly a Map
, hence IDE is complaining. 在func2
,我可以理解MyMap
并不完全是Map
,因此IDE抱怨。 After updating the signature like func3
it works again. 在像func3
更新签名后,它再次起作用。 As for func4
, I sort of thinking Map<?,?>
is not the same as a raw type Map
, thats why IDE is complaining again? 至于func4
,我认为Map<?,?>
与原始类型Map
不一样,这就是为什么IDE再次抱怨? But then what puzzles me most is func5
because it looks equivalent to func4
but IDE is not complaining? 但最让我困惑的是func5
因为它看起来相当于func4
但是IDE并不抱怨?
I think this was answered already: 我想这已经回答了:
Difference between Bounded Type parameter and Upper Bound Wildcard 有界类型参数与上限通配符的区别
Only exception, you added Raw Type Eresure, but I don't think it somehow influence the result. 只有例外,你添加了Raw Type Eresure,但我不认为它会以某种方式影响结果。
Also, I thinks you may find next useful: 另外,我认为你可能会发现下一个有用的:
main.func4((List<? extends Map<?, ?>>) myMap); // OK, but unchecked warning
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