[英]Specific string format in java
I want to validate a String in java that contains the following order: 我想在Java中验证包含以下顺序的字符串:
SAVA950720HMCLZL04
SAVA950720HMCLZL04
That is, four letters, six numbers, six letters and finally two numbers. 也就是说,四个字母,六个数字,六个字母以及最后两个数字。
I was reading about Regular Expressions but I can't understand how to implement it. 我在阅读正则表达式,但是我不明白如何实现它。
I did this method to validate the first four letters. 我使用这种方法来验证前四个字母。
public void name(String s){
Pattern pat=Pattern.compile("[a-zA-z]{4}");
Matcher mat=pat.matcher(curp);
if(mat.matches()){
JOptionPane.showMessageDialog(null, "Validating");
}else{
JOptionPane.showMessageDialog(null, "Check your data. please", "error",JOptionPane.ERROR);
}
}
I think that I might be wrong because I don't know how to implement it correctly, any help about what might be the correct solution to my problem?. 我认为我可能是错的,因为我不知道如何正确实现它,关于什么是正确解决我的问题的帮助?
Regex pattern in your case would be: 您的情况下的正则表达式模式为:
[a-zA-Z]{4}[0-9]{6}[a-zA-Z]{6}[0-9]{2}
Find matching is simple: 查找匹配很简单:
public void name(String s){
String pattern = "[a-zA-Z]{4}[0-9]{6}[a-zA-Z]{6}[0-9]{2}";
boolean match = s.matches(pattern);
if (match) {
...
} else {
...
}
}
You can test regex from here https://regex101.com/ 您可以从这里https://regex101.com/测试regex
Edit 编辑
I used [0-9] instead of \\d to ensure the safety matching for only digits. 我使用[0-9]而不是\\ d来确保仅数字的安全匹配。 More details can be found here: Should I use \\d or [0-9] to match digits in a Perl regex?
在这里可以找到更多详细信息: 我应该使用\\ d或[0-9]来匹配Perl正则表达式中的数字吗?
Matcher.match
attempts to match entire String against the pattern and your current pattern validates only 4 characters. Matcher.match
尝试将整个String与该模式匹配,并且您当前的模式仅验证4个字符。 Here is what you can do to test you regular expression: 这是测试正则表达式的方法:
.*
at the end of regular expression to match rest of the String .*
放在正则表达式的末尾以匹配字符串的其余部分 Matcher.find
or Matcher.lookingAt
to match against substring Matcher.find
或Matcher.lookingAt
与子字符串进行匹配 Your pattern has a typo, second interval is too wide Az
vs AZ
您的图案有错别字,第二个间隔太宽
Az
与AZ
Try this Regex pattern: 尝试以下正则表达式模式:
[a-zA-Z]{4}\d{6}[a-zA-Z]{6}\d{2}
The above will validate for four letters, six numbers, six letters and finally two numbers. 上面的代码将验证四个字母,六个数字,六个字母以及最后两个数字。
package com.stackoverflow._42635543;
import java.util.regex.Pattern;
public class Main {
public static void main(String[] args) {
Pattern pat = Pattern.compile("[A-Za-z]{4}[0-9]{6}[A-Za-z]{6}[0-9]{2}");
if (pat.matcher("SAVA950720HMCLZL04").matches()) {
System.out.println("match");
} else {
System.out.println("no match");
}
if (pat.matcher("SAVA950720HMCLZL045").matches()) {
System.out.println("match");
} else {
System.out.println("no match");
}
}
}
produces 产生
match
no match
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