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Question

Let's say I have a list of turtles and each turtle in this list has a own numeric variable foo. How can I elegantly extract the turtle with the lowest value stored in foo without iterating the whole list?

Thank you in advance!

Eric.

Answer 1

If you want the turtle in the list with the lowest value of foo , then you can sort the list of turtles by the foo value for each turtle and then pick off the first turtle in the list. For NetLogo v6.0 that would be (assuming foo is a turtle-own variable and turtle-list is your list of turtles):

first sort-by[[t1 t2] -> [foo] of t1 < [foo] of t2] turtle-list

Charles

Answer 2

it depends a bit on the context (how is the list structured, who owns it, how is it built and how frequently), but in general I'd save the list in it's own global/turtle-owned variable then use the primitive 'min-one-of' to query it. If you give a reproducible example I can help you apply this to code, but something to the effect of

globals [foo-list] 
;make foo-list;
let small_foo min-one-of [foo-list] 
show small_foo

Answer 3

When you say you have a 'list' of turtles, do you actually mean the data type list, or do you really have an agentset (which is the more usual NetLogo construction of a group of turtles)? If you have an agentset, look at the dictionary for the primitive with-min . You will want some construction like let small_foo agentsetname with-min [foo]