Vim regex：二进制数

Question

I want to match binary numbers in vim, 我想在vim中匹配二进制数，

such as 0b101 , 0b111010 , or 0b110 in 0b110; 如0b101时0b111010，或0b110在0b110;

but not 0b1013 , or 0b10 in 0b10c 但不0b1013，或0b10c 0b10

I am trying to do it like this in vim script: 我正在尝试在vim脚本中这样做：

syntax match Number "\v\W0[bB][01][01]*"

However, it also matches 0b101 in 0b101fa . 但是，它也匹配0b101fa中的0b101 。

Is there any way to match them correctly? 有什么办法可以正确匹配它们？

Thanks 谢谢

Answer 1

You can use these commands : 您可以使用以下命令：

:syntax match BinaryNb /\v<0[Bb][01]+>/
:highlight link BinaryNb Error

Demo : 演示：

Answer 2

Hexadecimal must match byte unit. 十六进制必须匹配字节单元。 Refer to following image. 请参考下图。