[英]How to replace repetitive punctuation in PHP using regex?
Let say, I have this 可以说,我有这个
Hello ??? WHERE ARE YOU!!!! Comon ?!?!?!
desired outout
Hello ? WHERE ARE YOU!!!! Comon ?!
How can I achieve this? 我该如何实现? I tried
preg_replace_callback
but to no luck. 我尝试了
preg_replace_callback
但是没有运气。 I used Finding the shortest repetitive pattern in a string as an starting point but it works on complete sentence, I need it to work on word by word + I need to remove duplicate computations only (patterns)? 我以查找字符串中最短的重复模式作为起点,但它适用于完整的句子,我需要它逐字处理+我只需要删除重复的计算(模式)? Live Code
现场代码
Replace \\?+
with ?
将
\\?+
替换为?
, !+
with !
,
!+
与!
, (\\?!)+
with ?!
,
(\\?!)+
与?!
, and so on. , 等等。
function dedup_punctuation($str) {
$targets = array('/\?+/', '/!+/', '/(\?!)+/');
$replacements = array('?' , '!' , '?!' );
return preg_replace($targets, $replacements, $str);
}
Use below code: 使用以下代码:
$str = "Hello ??? WHERE ARE YOU!!!! Comon ?!?!?! ...";
$replacement = [
'?',
'?!',
'.',
];
foreach( $replacement as $key => $value ){
$pattern[$key] = sprintf("/(\%s)+/", $value);
}
echo $outout = preg_replace($pattern, $replacement, $str);
Insert any punctuation to replacement array to delete repetitive punctuation. 将所有标点插入替换数组以删除重复的标点。
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