[英]how to replace text between 2 slashes with regex?
I have a src attribute that I only want to replace whatever dimensions happen to be between b1/
and /imglibrary
: b1/200x300/imglibrary
我有一个src属性,我只想替换
b1/
和/imglibrary
之间的任何尺寸: b1/200x300/imglibrary
<img class="Img" src="b1/200x300/imglibrary" alt=""/>
var $image = $('.Img').attr('src');
var editedImage = $image.replace(/b1\/.*?\/imglibrary/,"b1/800x600/imglibrary");
console.log(editedImage);
but the output is: /imglibrary/b1/800x600/imglibrary/
但输出为:
/imglibrary/b1/800x600/imglibrary/
I can't simply find and replace the text 200x300 because that text will change based on the image. 我不能简单地找到并替换200x300文本,因为该文本会根据图像而变化。 Can anyone please shed some light on where I am going wrong?
谁能告诉我我要去哪里错了?
Assuming, that you want to replace resolution value, which pattern looks like numberxnumber
, use following RegExp
: 假设您要替换分辨率值,该模式类似于
numberxnumber
,请使用以下RegExp
:
var $image = $('.Img').attr('src'); var editedImage = $image.replace(/(?!\\/)\\d+x\\d+(?=\\/)/, "800x600"); console.log(editedImage);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <img class="Img" src="b1/200x300/imglibrary" alt=""/>
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.