[英]Bash | pipe to bash function
In the attempt to pipe to a Bash function, I wrote this: 为了尝试传递到Bash函数,我这样写:
example () {
if [ -z ${1+x} ]; then local S=${@:-$(</dev/stdin)}; else local S="$1"; fi
#echo "$S"
echo "$S" | tr ' ' '_'
}
echo 'Moizès Júnior' | example
example 'Moizès Júnior'
Moizès_Júnior
Moizès_Júnior
However, in another context I am receiving the correct output plus this error message: "Segmentation fault (core dumped)". 但是,在另一种情况下,我收到的是正确的输出以及以下错误消息:“分段错误(内核已转储)”。
Trying to debug it I ask if there is something wrong the way I am writing the code inside the function in order to get STDIN. 尝试调试它时,我问我在函数内部编写代码的方式是否有问题以获得STDIN。
Thanks a lot. 非常感谢。
I wouldn't recommending reading the whole stdin into a variable. 我不建议将整个标准输入读入变量。 Instead of:
代替:
#the main "worker" function always uses stdin/out
example_worker() { tr ' ' '_'; }
#the switcher
example() { if [[ -z "$1" ]]; then example_worker; else example_worker <<< "$1"; fi ; }
echo 'a b c' | example
example 'a b c'
#but also
example < multi_giga_file.txt
If bash
is responsible for the core dump, that certainly indicates a bug in bash
that should be reported. 如果
bash
负责核心转储,那肯定表示应报告bash
中的错误。 However, your function can be written more simply as 但是,您的函数可以更简单地编写为
example () {
local S
if (( "$#" == 0 )); then
IFS= read -r S
set -- "$S"
fi
echo "${1// /_}"
}
which may, at least, avoid the bug. 至少可以避免该错误。
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