Python中C ++联合的等价物

Question

Say I have the following code in C++:

union {
    int32_t i;
    uint32_t ui;
};

i = SomeFunc();
std::string test(std::to_string(ui));
std::ofstream outFile(test);

And say I had the value of i somehow in Python, how would I be able to get the name of the file?

For those of you that are unfamiliar with C++. What I am doing here is writing some value in signed 32-bit integer format to i and then interpreting the bitwise representation as an unsigned 32-bit integer in ui . I am taking the same 32 bits and interpreting them in two different ways.

How can I do this in Python? There does not seem to be any explicit type specification in Python, so how can I reinterpret some set of bits in a different way?

EDIT: I am using Python 2.7.12

Answer 1

I would use python struct for interpreting bits in different ways.

something like following to print -12 as unsigned integer

import struct
p = struct.pack("@i", -12)
print("{}".format(struct.unpack("@I",p)[0]))