使用子进程在python 2.7中获取tail cmd输出

Question

I am trying to tail a file's content through python. The code I am using is as below

#! /usr/bin/python

import subprocess
import os.path

# Get the file path
filepath = os.path.join(baseDir,"filename.*" + uniqueId)
# Call subprocess and get last 10 lines from file
spTailFile = subprocess.Popen(["tail", "-10", filepath ], stdout=subprocess.PIPE)
tailOutput = spTailFile.communicate()[0]
print tailOutput

The above code throws an error as below:

tail: cannot open `/hostname/user/app/filename.*39102'

I see output if I execute the tail command with the filepath directly in bash.

tail -10 /hostname/user/app/filename.*39102

Why is subprocess passing an extra backtick (`) when executing the tail command?

Update:

I ended up using glob to find the file as @cdarke had suggested and then passing it to the Popen cmd.

Answer 1

Bash extends the '*', Popen not.

Two possibilities:.
1. Do it within your script and pass a filename without '*'.
2. Create a Bash script and call this from python.