[英]Search in Hashmap
Using for loop to compare the input value with the hashmap
if it matches any value in the hash-map then the code prints all the related values with that time. 如果输入值与
hashmap
中的任何值匹配,则使用for循环将输入值与hashmap
进行比较,然后代码将打印所有相关值。
The result shows out for me NULL
结果显示我为
NULL
System.out.println("Please enter time :");
Scanner scan = new Scanner(System.in);
String value = scan.nextLine();//Read input-time
Measurement measurement = measurements.get(value);//there can only be 1 Measurement for 1 time
if(measurement != null){
System.out.println(measurement);
}}
Class Measurement: 等级测量:
public void getTimeInfo(String value)
{
value = Measurements.get(time);
if (value == null) {
throw new MeasurementException();
}
System.out.println("The detailed info : " + this.time + "-" + this.temp+ " "+ this.wind+ "-" + this.humid );
}
}
}
Following the 3 steps (ignoring the Json part) u mentioned and reusing some of your code i can provide u this code: 按照你提到的三个步骤(忽略Json部分)并重用你的一些代码,我可以提供你的代码:
Main.java : Main.java :
public class Main {
static HashMap<String, Measurement> measurements = new HashMap();
public static void main(String[] args) {
for (int i = 0; i < 3; i++) {//Create 3 measurements
String time = ""+i;
measurements.put(time, new Measurement(time, (float) i, (float) i, (float) i));
}
System.out.println("Please enter time :");
Scanner scan = new Scanner(System.in);
String value = scan.nextLine();//Read input-time
Measurement measurement = measurements.get(value);//there can only be 1 Measurement for 1 time
if(measurement != null){
System.out.println(measurement);
}
}
}
Measurement.java : Measurement.java :
public class Measurement {
String time ;
Float temp;
Float wind;
Float humid;
int iD;
public Measurement(String d, Float t, Float w, Float h){
this.time = d;
this.temp = t;
this.wind = w;
this.humid = h;
}
@Override
public String toString() {
return "The detailed info : " + this.time + "-" + this.temp+ " "+ this.wind+ "-" + this.humid;
}
}
It might not fit exactly your needs but it can be a help. 它可能不完全符合您的需求,但它可以是一个帮助。
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