[英]Open app from messages extension in swift 3
I'm trying to open my mother app from message extension on a click of button. 我正在尝试通过单击按钮从消息扩展名打开我的母亲应用程序。 I've used this code in my exstension:
我在扩展中使用了以下代码:
@IBAction func open(_ sender: UIButton) {
let url = URL(string: "swiftexamples://")
self.extensionContext?.open(url!, completionHandler: {(succes) in })
}
Everything works fine when my mother app is running and backgrounded, however when i want to open closed app, it crashes. 当我的母亲应用程序运行并进入后台时,一切正常,但是当我要打开关闭的应用程序时,它崩溃。 There are no crash logs, i have simmilar situation to this iOS app crashes when first opened by URL Scheme .
没有崩溃日志, 当我第一次由URL Scheme打开时 ,我对此iOS应用程序崩溃的情况很相似。 I'm quite sure i have to add something to app delegate.
我很确定我必须向应用程序委托中添加一些内容。 I've found function application(_:open:options:).
我找到了函数application(_:open:options :)。 The problem is, i don't now how to implement "option" part.
问题是,我现在不执行“选项”部分。 I've written this:
我写了这个:
func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
// Override point for customization after application launch.
let url = launchOptions?[UIApplicationLaunchOptionsKey.url] as? NSURL
let sourceApp = launchOptions?[UIApplicationLaunchOptionsKey.sourceApplication] as? String
let annotation = launchOptions?[UIApplicationLaunchOptionsKey.annotation] as? AnyObject
self.application(application, open: url, options:[sourceApp: String, annotation:AnyObject] )
return true
}
Also i've heard about Universal Links and that they have similar abilities to url schemes. 我也听说过通用链接,它们具有与url方案相似的功能。 Is it possible to do achive what i want using universal links ?
是否可以使用通用链接来实现我想要的功能?
You can try this solution. 您可以尝试此解决方案。 It worked for me:
它为我工作:
func openUrl(url: URL?) {
let selector = sel_registerName("openURL:")
var responder = self as UIResponder?
while let r = responder, !r.responds(to: selector) {
responder = r.next
}
_ = responder?.perform(selector, with: url)
}
func canOpenUrl(url: URL?) -> Bool {
let selector = sel_registerName("canOpenURL:")
var responder = self as UIResponder?
while let r = responder, !r.responds(to: selector) {
responder = r.next
}
return (responder!.perform(selector, with: url) != nil)
}
As proposed in https://stackoverflow.com/a/44694703/2064473 如https://stackoverflow.com/a/44694703/2064473中所建议
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