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通过Swift 3中的邮件扩展程序打开应用

[英]Open app from messages extension in swift 3

I'm trying to open my mother app from message extension on a click of button. 我正在尝试通过单击按钮从消息扩展名打开我的母亲应用程序。 I've used this code in my exstension: 我在扩展中使用了以下代码:

    @IBAction func open(_ sender: UIButton) {

    let url = URL(string: "swiftexamples://")

    self.extensionContext?.open(url!, completionHandler: {(succes) in })


}

Everything works fine when my mother app is running and backgrounded, however when i want to open closed app, it crashes. 当我的母亲应用程序运行并进入后台时,一切正常,但是当我要打开关闭的应用程序时,它崩溃。 There are no crash logs, i have simmilar situation to this iOS app crashes when first opened by URL Scheme . 没有崩溃日志, 当我第一次由URL Scheme打开时 ,我对此iOS应用程序崩溃的情况很相似。 I'm quite sure i have to add something to app delegate. 我很确定我必须向应用程序委托中添加一些内容。 I've found function application(_:open:options:). 我找到了函数application(_:open:options :)。 The problem is, i don't now how to implement "option" part. 问题是,我现在不执行“选项”部分。 I've written this: 我写了这个:

    func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
    // Override point for customization after application launch.
     let url = launchOptions?[UIApplicationLaunchOptionsKey.url] as? NSURL 
       let sourceApp = launchOptions?[UIApplicationLaunchOptionsKey.sourceApplication] as? String
       let annotation = launchOptions?[UIApplicationLaunchOptionsKey.annotation] as? AnyObject

        self.application(application, open: url, options:[sourceApp: String, annotation:AnyObject] )



    return true
}

Also i've heard about Universal Links and that they have similar abilities to url schemes. 我也听说过通用链接,它们具有与url方案相似的功能。 Is it possible to do achive what i want using universal links ? 是否可以使用通用链接来实现我想要的功能?

You can try this solution. 您可以尝试此解决方案。 It worked for me: 它为我工作:

func openUrl(url: URL?) {
    let selector = sel_registerName("openURL:")
    var responder = self as UIResponder?
    while let r = responder, !r.responds(to: selector) {
        responder = r.next
    }
    _ = responder?.perform(selector, with: url)
}

func canOpenUrl(url: URL?) -> Bool {
    let selector = sel_registerName("canOpenURL:")
    var responder = self as UIResponder?
    while let r = responder, !r.responds(to: selector) {
        responder = r.next
    }
    return (responder!.perform(selector, with: url) != nil)
}

As proposed in https://stackoverflow.com/a/44694703/2064473 https://stackoverflow.com/a/44694703/2064473中所建议

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