[英]Query data by year from joined table
I have one table named colors
and I need to create a query that returns how many unique colors are used each year based on the date in my other table, programs
. 我有一个名为
colors
表,我需要创建一个查询,该查询根据其他表( programs
的日期返回每年使用多少种独特的颜色。 It looks like this: 看起来像这样:
colors
+----+----------+
| id | name |
+----+----------+
| 1 | blue |
| 2 | yellow |
+----+----------+
programs
+----+------------+
| id | date |
+----+------------+
| 1 | 2016-01-08 |
| 2 | 2016-02-08 |
| 3 | 2017-02-08 |
+----+------------+
programs_colors
+------------+----------+
| program_id | color_id |
+------------+----------+
| 1 | 1 |
| 1 | 1 |
| 2 | 2 |
| 2 | 1 |
| 3 | 1 |
| 3 | 1 |
+------------+----------+
I have tried with this: 我已经尝试过:
SELECT min(date), count(*) FROM (
SELECT min(date) AS date FROM programs_colors INNER JOIN programs ON programs.id = program_id GROUP BY color_id
) AS a GROUP BY year(date)
min(date): count(*):
2016-01-08 2
2017-01-08 0
But the above query groups my colors as a whole, but I need them grouped by each year 但是上面的查询将我的颜色总体上分组,但是我需要将它们按每年分组
Expected result: 预期结果:
min(date): count(*):
2016-01-08 2
2017-01-08 1
I hope my question makes sense 我希望我的问题有道理
If I understand right, you might need to do something like this 如果我理解正确,那么您可能需要执行以下操作
SELECT min(date), sum(count) FROM (
SELECT min(date) AS date, count(*) as count FROM programs_colors INNER JOIN programs ON programs.id = program_id GROUP BY color_id
) AS a GROUP BY year(date)
SELECT min(date), count(distinct color_id)
FROM programs_colors
INNER JOIN programs
ON programs.id = program_id
GROUP BY year(date);
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