[英]Hibernate Many To Many unidirectional mapping
I have two tables USERS and FILES. 我有两个表USERS和FILES。 I want to be able to control the users that can download a file, and for this I was thinking of creating and intermediary table FILE_PERMISSIONS with a user_id and a file_id.
我希望能够控制可以下载文件的用户,为此,我正在考虑创建一个带有user_id和file_id的中间表FILE_PERMISSIONS。
Looking at database level I understand how can I solve the problem, but going up at Hibernate level, I can't really understand how should I map this relation. 从数据库级别看,我知道如何解决该问题,但是在Hibernate级别,我真的不明白如何映射此关系。 The way I see it is something like this:
我的看法是这样的:
public class User {
private Integer userId;
}
public class File {
private Integer fileId;
private List<Integer> userIds;
}
So I want my File object to know the id property of all the users that can download the file, but not vice versa, so that a user doesn't know about those files. 因此,我希望我的File对象知道所有可以下载文件的用户的id属性,但反之则不然,这样用户就不知道这些文件。
From what I read I can use a many to many unidirectional relation but I'm not sure that I can only have the id of the user, and not the user object itself. 从我阅读的内容中,我可以使用多对多的单向关系,但是我不确定只能拥有用户的ID,而不能拥有用户对象本身。
You can manage it having the following structure. 您可以使用以下结构进行管理。
User: 用户:
@Entity
public class User {
@Id
private Integer userId;
// getters, setters
}
File: 文件:
@Entity
public class File {
@Id
private Integer fileId;
@ManyToMany
@JoinTable(
name = "file_permissions",
joinColumns = @JoinColumn(name = "file_id"),
inverseJoinColumns = @JoinColumn(name = "user_id")
)
private Set<User> users;
// getters, setters
}
You can benefit from making an easier design using @OneToMany relationship instead. 您可以使用@OneToMany关系来简化设计,从而从中受益。 This way you could create a service in order to manage File permissions, instead of relying on user service or file services to do so.
这样,您可以创建服务来管理文件权限,而不必依赖用户服务或文件服务来创建服务。
I propose something like: 我建议类似:
User.java User.java
@Entity
public class User {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Integer id;
@Version
private Integer version;
@OneToMany(cascade = CascadeType.ALL, mappedBy = "user", orphanRemoval = true)
private List<FilePermissions> filePermissionsList= new ArrayList<>();
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public List<FilePermissions> getFilePermissionsList() {
return filePermissionsList;
}
public void setFilePermissionsList(List<FilePermissions> filePermissionsList) {
this.filePermissionsList = filePermissionsList;
}
}
Notice User has a list of FilePermissions. 注意用户具有FilePermissions列表。
Your FilePermission class should be like: 您的FilePermission类应类似于:
@Entity
public class FilePermissions {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Integer id;
@Version
private Integer version;
@ManyToOne
private User user;
@OneToOne
private File file;
private Permission permission;
public FilePermissions() {
}
public FilePermissions(User user, File file, Permission permission) {
this.user = user;
this.file = file;
this.permission = permission;
}
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public Integer getVersion() {
return version;
}
public void setVersion(Integer version) {
this.version = version;
}
public User getUser() {
return user;
}
public void setUser(User user) {
this.user = user;
}
public File getFile() {
return file;
}
public void setFile(File file) {
this.file = file;
}
public Permission getPermission() {
return permission;
}
public void setPermission(Permission permission) {
this.permission = permission;
}
}
Notice the @ManytoOne relationship back to the user, as well as the @OneToOne relationship to the File class. 注意@ManytoOne关系回到用户,以及@OneToOne关系回到File类。 Here you can store the detail on what permission user have, in this case i have a enumeration.
在这里,您可以存储有关权限用户拥有的详细信息,在这种情况下,我有一个枚举。
Your File class is straight forward: 您的File类很简单:
@Entity
public class File {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Integer id;
@Version
private Integer version;
private String name;
public File() {}
public File(String name) {
this.name = name;
}
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
You can see solution in detail here: https://github.com/ccoloradoc/HibernateFilePermissionSample 您可以在此处详细查看解决方案: https : //github.com/ccoloradoc/HibernateFilePermissionSample
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